Tensile strength

Imagine a spring attached at one end to a support and at rest (with no action at all).

When we apply a force F to the other end, the spring tends to warp (stretch or compress depending on the direction of the applied force).

In studying spring deformations and applied forces, Robert Hooke (1635-1703) found that spring deformation increases proportionally to force. Hence the following law, called Hooke's Law, was established:


F: intensity of the applied force (N);

k: spring elastic constant (N / m);

x: spring deformation (m).

The elastic constant of the spring depends mainly on the nature of the spring manufacturing material and its dimensions. Its most usual unit is N / m (newton per meter) but we also find N / cm; kgf / m, etc.


A 10kg body in equilibrium is attached to the end of a spring whose elastic constant is 150N / m. Considering g = 10m / s², what will be the spring deformation?

If the body is in equilibrium, the sum of the forces applied to it will be null, ie:

, because the forces have opposite directions.