## Electric charges

**1.** An initially neutral conductive body loses . Considering the elemental load What will be the electrical charge in the body after this loss of electrons?

*Initially we will think of the sign of the charge. If the body has lost electrons, it has lost a negative charge, thus becoming more positively charged, thus positively charged.*

*As for the numerical resolution of the problem, we must remember the equation of electric charge quantization:*

*Being ***no*** The number of electrons that changes the body's charge:*

*Therefore, the load on the driver will be .*

**2.** A body has and . Considering the elemental load , what is the burden of this body?

*First we find that the body has more protons than electrons, so the body is positively electrified, with charge equivalent to the difference between the amount of protons and electrons.*

*This charge is calculated by: *

## Body electrification

**1. **In one activity in the physics lab, a student, wearing a glove of insulating material, touches a metal sphere A, charged with +8 µC charge, on an identical electrically neutral B. It then touches sphere B into another C, also identical and electrically neutral. What is the charge of each sphere?

*Solving the piecemeal exercise.*

*First we calculate the load resulting from the first contact by their arithmetic mean:*

*As sphere A no longer makes contact with any other sphere, its final charge is +4 µC.*

*Calculating the second contact of sphere B, with sphere C now, we have:*

*Therefore, the final loads of the 3 spheres are:*

## Coulomb's Law

**1.** Consider two particles loaded with +2.5 µC and -1.5 µC respectively, arranged as shown below:

How strong is the force acting on load 2?

*Analyzing the signs of the loads we can conclude that the force calculated by Coulomb's law will be of attraction, having the calculation of its module given by:*

*Therefore the force of attraction acting on the load 2 has a modulus 0,375N and its vector can be represented as:*