1. An initially neutral conductive body loses . Considering the elemental load What will be the electrical charge in the body after this loss of electrons?
Initially we will think of the sign of the charge. If the body has lost electrons, it has lost a negative charge, thus becoming more positively charged, thus positively charged.
As for the numerical resolution of the problem, we must remember the equation of electric charge quantization:
Being no The number of electrons that changes the body's charge:
Therefore, the load on the driver will be .
2. A body has and . Considering the elemental load , what is the burden of this body?
First we find that the body has more protons than electrons, so the body is positively electrified, with charge equivalent to the difference between the amount of protons and electrons.
This charge is calculated by:
1. In one activity in the physics lab, a student, wearing a glove of insulating material, touches a metal sphere A, charged with +8 µC charge, on an identical electrically neutral B. It then touches sphere B into another C, also identical and electrically neutral. What is the charge of each sphere?
Solving the piecemeal exercise.
First we calculate the load resulting from the first contact by their arithmetic mean:
As sphere A no longer makes contact with any other sphere, its final charge is +4 µC.
Calculating the second contact of sphere B, with sphere C now, we have:
Therefore, the final loads of the 3 spheres are:
1. Consider two particles loaded with +2.5 µC and -1.5 µC respectively, arranged as shown below:
How strong is the force acting on load 2?
Analyzing the signs of the loads we can conclude that the force calculated by Coulomb's law will be of attraction, having the calculation of its module given by:
Therefore the force of attraction acting on the load 2 has a modulus 0,375N and its vector can be represented as: